math
posted by mota on .
I have a question in
(( distance between two points ))
show that A(4,2), B(2,2) and C(2,8)are the vertices of an isoceles right triangle.
please in detales .. thank u

The lengths of the sides are
AB: sqrt(6^2 + 4^2) = sqrt 52 (side c)
BC: sqrt (4^2 + 6^2) = sqrt 52 (side a)
AC: sqrt (2^2 + 10^2) = sqrt 104 (side b)
This proves that two sides are equal and that it is a right triangle since
c^2 + a^2 = b^2.