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February 1, 2015

February 1, 2015

Posted by **Lindsay** on Friday, November 9, 2007 at 9:16pm.

Bobpursley showed me how to do this, and he got 17.42 m/s. However, this is not correct. This answer assumes the ball is caught by moving the arms of the goalie. Is there any other way I can go about solving this?

- Physics -
**drwls**, Friday, November 9, 2007 at 11:18pmThe time to reach the goat is

T = 23.05m/(17.97 cos 25.83)= 1.435 s

The horizontal velocity component remains 17.97 cos 25.83 = 16.17 m/s

The vertical velocity component when it reaches the goalie is

17.97 sin 23.85 - g T = 9.747-14.063

= -4.316 m/s (It is coming down)

The speed is sqrt[(16.17^^2 + (-4.32)^2] = 16.73 m/s

- Physics -
**Lindsay**, Friday, November 9, 2007 at 11:37pm16.73 is the final?? Because again, it's not right. Hmm...

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