Posted by **Lindsay** on Friday, November 9, 2007 at 9:16pm.

The soccer goal is 23.05 m in front of a soccer player. She kicks the ball giving it a speed of 17.97 m/s at an angle of 25.83 degrees from the horizontal. If the goalie is standing exactly in front of the net, find the speed of the ball just as it reaches the goalie.

Bobpursley showed me how to do this, and he got 17.42 m/s. However, this is not correct. This answer assumes the ball is caught by moving the arms of the goalie. Is there any other way I can go about solving this?

- Physics -
**drwls**, Friday, November 9, 2007 at 11:18pm
The time to reach the goat is

T = 23.05m/(17.97 cos 25.83)= 1.435 s

The horizontal velocity component remains 17.97 cos 25.83 = 16.17 m/s

The vertical velocity component when it reaches the goalie is

17.97 sin 23.85 - g T = 9.747-14.063

= -4.316 m/s (It is coming down)

The speed is sqrt[(16.17^^2 + (-4.32)^2] = 16.73 m/s

- Physics -
**Lindsay**, Friday, November 9, 2007 at 11:37pm
16.73 is the final?? Because again, it's not right. Hmm...

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