Saturday

February 28, 2015

February 28, 2015

Posted by **Anita** on Friday, November 9, 2007 at 7:53pm.

A boater travels 16 miles per hour on the water on a still day. During one particular windy day, he finds that he travels 48 miles with the wind behind him in the same amount of time that he travels 16 miles into the wind. Find the rate of the wind.

- algebra (23) -
**Reiny**, Friday, November 9, 2007 at 11:07pmthis one is similar to the previous two questions you asked and were helped by bobpursley.

Remember Time = Distance/Rate, so..

Time for first case = 48/(16+x)

time for second case = 16/(16-x)

but the times were the same

48/(16+x) = 16/(16-x)

cross-multiply and solve for x

**Answer this Question**

**Related Questions**

Math- Multi-step word problems - A canoe in still water travels at a rate of 10 ...

algebra 1A - a family travels to Bryce Canyon for three days. on the first day, ...

word problems - A canoe in still water travels at a rate of 12 miles per hour. ...

intermediate algebra - a motorboat moves 25 miles per hour in still water. it ...

Math - Alicia went on a steamboat ride up the Mississippi River. The boat ...

math - Alicia went on a steamboat ride up the Mississippi River. The boat ...

Math - Alicia went on a steamboat ride up the Mississippi River. The boat ...

PLEASE HELP MEEE!!!! - A canoe in still water travels at a rate of 12 miles per ...

Math - 6. Columbus' ships covered approximately 144 miles a day. How many miles ...

Algebra - 2 cyclists travel opposite on circular trail that is 5 miles long. one...