Homework Help: algebra (23)

Posted by Anita on Friday, November 9, 2007 at 7:53pm.

How do you set up this problem?
A boater travels 16 miles per hour on the water on a still day. During one particular windy day, he finds that he travels 48 miles with the wind behind him in the same amount of time that he travels 16 miles into the wind. Find the rate of the wind.

algebra (23) - Reiny, Friday, November 9, 2007 at 11:07pm
this one is similar to the previous two questions you asked and were helped by bobpursley.

Remember Time = Distance/Rate, so..

Time for first case = 48/(16+x)
time for second case = 16/(16-x)

but the times were the same

48/(16+x) = 16/(16-x)

cross-multiply and solve for x

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