Monday
September 22, 2014

Homework Help: Mathematics - Trigonometric Identities

Posted by Anonymous on Thursday, November 8, 2007 at 6:17pm.

Let y represent theta

Prove:

1 + 1/tan^2y = 1/sin^2y



My Answer:

LS:

= 1 + 1/tan^2y
= (sin^2y + cos^2y) + 1 /(sin^2y/cos^2y)
= (sin^2y + cos^2y) + 1 x (cos^2y/sin^2y)
= (sin^2y + cos^2y) + (sin^2y + cos^2y) (cos^2y/sin^2y)
= (sin^2y + cos^2y) + (sin^2y + cos^2y)(sin^2y) / (sin^2y)(cos^2y/sin^2y)

... And now I confuse myself

Where did I go wrong? And please direct me on how to fix it?

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