Use the digits 0, 2, and 5 to make a 3 digit number that has both 2 and 5 as factors.
The possible numbers are:
250
205
520
502
Numbers that are divisible by 2 end in even numbers (2, 4, 6, 8, 0)
Numbers that are divisible by 5 end in either 0 or 5.
Which two numbers above are divisible by both 2 and 5?
If you post your answer, we'll be glad to check it.
250
To create a 3-digit number that has both 2 and 5 as factors using the digits 0, 2, and 5, we need to find a number that is divisible by both 2 and 5.
Since we want the number to have both 2 and 5 as factors, we know that the last digit should be 0 or 5 because multiples of 5 must end in 0 or 5.
Let's consider the possible combinations:
1. 520: This number is not divisible by 2, so it cannot be the answer.
2. 205: This number is divisible by 5, but not by 2, so it also cannot be the answer.
3. 250: This number is divisible by both 2 and 5, making it a valid solution.
Therefore, the three-digit number that has both 2 and 5 as factors using the digits 0, 2, and 5 is 250.