Posted by Lindsay on Wednesday, November 7, 2007 at 9:09pm.
The vertical component of velocity at max height is zero. The horizontal component remains Vh during flight, and that is the speed at max height. Let Voy be the initial vertical component of the launch speed.
(launch speed)^2 = Voy^2 + Vh^2
= (6.4 Vh)^2 = 40.96 Vh^2
Voy^2 = 39.96 Vh^2
Voy = 6.32 Vh
launch angle arctan(Voy/Vh) = arctan 6.32 = 81.0 degrees
How did you come up with 39.96 Vh^2?
I squared 6.4 and subracted 1. See the formula
Voy^2 + Vh^2 = 40.96 Vh^2
This is probably really obvious, but I'm still not undertanding why you have to subtract one.
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