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October 25, 2014

October 25, 2014

Posted by **Christina** on Wednesday, November 7, 2007 at 5:38pm.

The moment of inertia about the axis of rotation of the remainder of his body is constant and equal to 0.350 kg*m^2 If the skater's original angular speed is 0.450 rev/s, what is his final angular speed?

- Physics -
**drwls**, Wednesday, November 7, 2007 at 6:55pmUse conservation of angular momentum. Assume the outstretched arms have a moment of inertia contribution of

Iarms2 = (1/3) M(arms) L^2, where L = 1.80m m.

[(Ibody + Iarms1)w1] = [(Ibody + Iarms2)w2]

Solve for w2

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