Tuesday

September 30, 2014

September 30, 2014

Posted by **Christina** on Wednesday, November 7, 2007 at 5:38pm.

The moment of inertia about the axis of rotation of the remainder of his body is constant and equal to 0.350 kg*m^2 If the skater's original angular speed is 0.450 rev/s, what is his final angular speed?

- Physics -
**drwls**, Wednesday, November 7, 2007 at 6:55pmUse conservation of angular momentum. Assume the outstretched arms have a moment of inertia contribution of

Iarms2 = (1/3) M(arms) L^2, where L = 1.80m m.

[(Ibody + Iarms1)w1] = [(Ibody + Iarms2)w2]

Solve for w2

**Answer this Question**

**Related Questions**

physics - The outstretched hands and arms of a figure skater preparing for a ...

Physics - The Spinning Figure Skater. The outstretched hands and arms of a ...

Physics - A figure skater rotates about a vertical axis through her center with ...

ice skater world problem - A skater spins with an angular speed of 12.4 rad/s ...

physics - An ice skater has a moment of inertia of 2.3 kg * m^2 when his arms ...

Physics - An ice skater spins with his arms outstretched. When he pulls his arms...

physics - a skater holds her arms outstretched as she spins at 140 rpm. What is ...

physics - Two fi gure skaters are moving east together during a performance. ...

Physics - A figure skater is spinning with her arms out wide. Will she spin ...

physics - A figure skater is spinning at a rate of 1.7 rev/s with her arms ...