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April 25, 2014

Homework Help: Physics

Posted by Andrea on Wednesday, November 7, 2007 at 5:06pm.

A lever is 5m long. The distance from fulcrum to the weight to be lifted is 1m. If the worker pushes on the opposite end with 400N, what is the max weight that can be lifted?

l=5m
h=1m
F=400N
F_g=?

torque=F_g*l
I first must find torque so that I can plug it into the above equation.
F=torque/r
400N=torque/5m
=2000Nm

thus
200Nm =F_g(5m)
F_g=400N

is this correct? Or would r=1m? Does the 1m in the question matter for this problem? Or is it just extra information?

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