Posted by Jessica on Wednesday, November 7, 2007 at 1:11pm.
Linear momentum is conserved. Whatever the momentum A lost in the collision, B gained.
I will be happy to critique your thinking.
Ball A's original momentum is .00114 kgm/s. The change in Ball A's momentum would be .006 kg x (.19 - .08) m/s, correct? Ball B's change in momentum would be .009 kg x (.11 - v) m/s. The momentum of Ball B would be .009 x the change in velocity from the previous question. Ball B's speed would be the original velocity minus the change in velocity.
Ball A's original momentum is .00114 kgm/s. The change in Ball A's momentum would be .006 kg x (.19 - .08) m/s, correct? Ball B's change in momentum would be .009 kg x (.11 - v) m/s. The momentum of Ball B would be .009 x the change in velocity from the previous question. Ball B's speed would be the original velocity minus the change in velocity.
Correct on the change of A momentum.
Ball B change in momentum is equal to the change in A momentum, not the change in A velocity.
New Ball B momentum:
.009*.11+ .006(.19-.08)
From that, you determine B velocity (by dividing the Momentum my mass B)
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