Posted by Hector on Tuesday, November 6, 2007 at 7:13pm.
1. You have the balanced equation.
2. Convert g Cu to mols Cu.
3. Convert g HNO3 to mols HNO3.
4a. Convert mols Cu to mols Cu(NO3)2.
4b. Convert mols HNO3 to mols Cu(NO3)2.
4c. Choose the smaller mols of Cu(NO2)2 2. The reagent producing that number (either 4a or 4b) will be the limiting reagent.
5. Convert mols of the limiting reagent to mols of the other reagent. That will be how much of the other reagent (the excess reagent) is used.
6. Convert mols of the excess reagent used to grams, subtract from the initial mass present, and that will give you the amount remaining after reaction.
Post your work if you need more help.
89
Related Questions
chemistry - copper metal reacts with nitric acid. assume that the reaction is ...
chemistry - How many grams NO gas can be produced from 110mL of 4.00 M HNO3 and ...
chemistry - How many g NO gas can be produced from 120 mL of 2.80 M HNO3 and ...
chemistry - in a reaction of 3Cu(s)+ 8HNO3(aq)¨ 3Cu(NO3)2(aq) +2NO(g...
Chemistry - How many grams of nitrogen monoxide gas can be produced from 80.0 ...
Chemistry - How many grams of nitrogen monoxide gas can be produced from 80.0 ml...
Chemistry - 1) A double displacement reaction takes place when aqueous sodium ...
CHEM! (SCIENCE) NEED HELP - How many moles of water will form if the reaction ...
Chemistry - 3Cu+8HNO3--> 3Cu(NO3)2+ 2NO+4H2O How many moles of HNO3 are ...
Chemistry - How many grams of NO gas can be produced from 80.0mL of 4.00M HNO3 ...
For Further Reading
