posted by Lindsay on .
A catapult on a cliff launches a large round rock towards a ship on the ocean below. The rock leaves the catapult from a height H = 35.0 m above sea level, directed at an angle theta = 46.7° above the horizontal, and with a speed v = 28.4 m/s. Assuming that air friction can be neglected, calculate the horizontal distance D traveled by the projectile.
Could someone give me the first step? I know that I will eventually use delta x = vx x t, but what do I need to do before that?
The first step is the vertical equation, to determine the time in air.
Determine the vertical and horizontal components of the initial velocity.
Hfinal=Hinitial + Viv*t - 1/2 g t^2
solve for t, the time in air. Then work the horizontal equation.
Height reached above the cliff is h = V^2sin^2(µ)/9.8.
t1 = Vsin(µ)/9.8.
h + 35 = 9.8t2^2/2---->t2
d = Vcos(µ)(t1 + t2)