Posted by **Lindsay** on Tuesday, November 6, 2007 at 2:14pm.

A stone is aimed at a cliff of height h with an initial speed of 62 m/s directed 45° above the horizontal, as shown in the Figure below. The stone strikes at A, 6.56 s after launching. What is the height of the cliff?

Can someone please tell me which equation(s) I need to use for this?

- Physics -
**bobpursley**, Tuesday, November 6, 2007 at 2:39pm
Not knowing where A is, it is going to be general.

Break the initial velocity into vertical and horizontal components. Then, using those, and the time of flight, you have two equations which should solve the problem:

Horizontal

distance= vih*time

Vertical:

height= viv*time - 4.9 time^2

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