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2 times a number increased by 28 is less than or equal to 6 times a number?
I'll delete any further math questions from you.
As Writeacher posted, we usually ignore many posts in a row from the same person -- especially when you apparently have made no effort to solve these yourself.
We do not do homework for students. We help them find their own answers.
We'll be glad to check YOUR work.
28+2x=≤
28+2n=≤6n
To solve this inequality, we'll define a variable to represent the unknown number. Let's call it "x". Now, let's translate the given inequality into an algebraic expression:
2x + 28 ≤ 6x
We want to isolate the variable, so let's start by subtracting 2x from both sides of the inequality:
2x - 2x + 28 ≤ 6x - 2x
28 ≤ 4x
To further isolate the variable, we divide both sides by 4:
28/4 ≤ 4x/4
7 ≤ x
Therefore, the original inequality is satisfied when the unknown number (x) is greater than or equal to 7.