we are working at an assembly plant making wooden toy giraffes. At the end of the line,the giraffes go horizontally off the edge of the conveyor belt and fall into a box bellow.If the box is 0.6 m below the level of the conveyor belt and 0.4 m away from it,what must be the horizontal velocity of giraffes as they leave the conveyor belt? thank you

Calculate the time it takes to fall 0.6 m. Call it T.

0.6 m = (1/2) gT^2
Solve for T.
The horizontal distance where it falls (X = 0.4 m) is the conveyor belt horizontal velocity V, multiplied by T
Solve for V.
V = X/T

To determine the horizontal velocity of the giraffes as they leave the conveyor belt, you can use the principles of projectile motion. The giraffes' motion in the horizontal direction is not affected by gravity since there are no forces acting horizontally.

The first step is to find the time it takes for the giraffes to fall 0.6 m vertically. We can use the equation of motion, assuming the initial vertical velocity is zero, and the final displacement is -0.6 m (since it falls downward):

s = ut + (1/2)at^2

Where:
s = displacement (vertical distance)
u = initial vertical velocity
t = time
a = acceleration due to gravity (9.8 m/s^2)

Rearranging the equation for time (t), we get:

t = sqrt((2s) / a)

t = sqrt((2(-0.6)) / 9.8) ≈ 0.11 seconds

Now that we know the time it takes for the giraffes to fall, we can find the horizontal distance it travels (0.4 m) during that time. Since velocity equals distance divided by time:

v = d / t

v = 0.4 m / 0.11 seconds ≈ 3.64 m/s

Therefore, the horizontal velocity of the giraffes as they leave the conveyor belt should be approximately 3.64 m/s.