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November 26, 2014

November 26, 2014

Posted by **dave** on Monday, November 5, 2007 at 10:52pm.

so i drew a small picture depicting it but i'm still confused on what to do. am i basically finding the rate of change?? as in the DR/DT? i need someone to explain this to me, pleaseee! thank you.

- calculus : related rates -
**Reiny**, Tuesday, November 6, 2007 at 1:15amcall the angle of elevation α (alpha)

so what you want to find is dα/dt

from your triangle

tan α = x/30, where x is the height of the balloon

then x = 30 tan α

and dx/dt = 30 (sec^2 α)dα/dt

when x = 30 , α = 45º and sec^2 45º = 2

so 3 = 30(2)dα/dt

and finally

dα/dt = 1/10

when the ballooon is 30 m hight, dα/dt = 1/10 radians/sec

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