Posted by **dave** on Monday, November 5, 2007 at 10:52pm.

a balloon rises at a rate of 3 meters per second from a point on the ground 30 meters from an observer. find the rate of change of the angle of elevation of the balloon from the observer when the balloon is 30 meters above the ground...

so i drew a small picture depicting it but i'm still confused on what to do. am i basically finding the rate of change?? as in the DR/DT? i need someone to explain this to me, pleaseee! thank you.

- calculus : related rates -
**Reiny**, Tuesday, November 6, 2007 at 1:15am
call the angle of elevation α (alpha)

so what you want to find is dα/dt

from your triangle

tan α = x/30, where x is the height of the balloon

then x = 30 tan α

and dx/dt = 30 (sec^2 α)dα/dt

when x = 30 , α = 45º and sec^2 45º = 2

so 3 = 30(2)dα/dt

and finally

dα/dt = 1/10

when the ballooon is 30 m hight, dα/dt = 1/10 radians/sec

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