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April 17, 2014

April 17, 2014

Posted by **Mary** on Monday, November 5, 2007 at 10:09pm.

_________ T

B = (4pi x 10^-7)(12.0) / (6.5 x 10^-3)(4pi (0.170^2))

B = 0.000015082 / 0.002360899

B = 6.39 x 10^-3T

- Physic please check -
**drwls**, Tuesday, November 6, 2007 at 6:20amB = mu H = (4 pi*10^-7)*i N/(2 r)

N is the number of turns.

r is the coil radius

i is the current

i = V/R

R = N* 2 pi r * (6.5*10^-3 ohm/m)

B = [(4 pi*10^-7)*V*N]/[(N*4*pi*r^2*(6.5*10^-3)]

= 10^-7 V/[r^2*(6.5*10^-3 ohm/m)]

The 4 pi factors and the number of turns N both cancel out. I agree with your formula and answer.

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