Posted by **Elizabeth White** on Monday, November 5, 2007 at 5:19pm.

Please help me solve the problem: A mixture of 12 ounces of vinegar and oil is 40 percent vinegar by weight. How many ounces oil must be added to the mixture to produce a new mixture that is only 25 percent vinegar?

- Math -
**DrBob222**, Monday, November 5, 2007 at 5:36pm
12 oz @ 0.4 = 4.8 oz vinegar.

12 oz @ 0.6 = 7.2 oz oil.

You want 25% of some volume to be 4.8 oz vinegar.

0.25 X = 4.8

X = 19.2 total volume.

You had 12 oz; therefore, you must add 19.2 - 12.0 oz oil or you must add 7.2 oz oil to make a final volume of 19.2 oz.

You can check it to see if it is right.

4.8 oz vinegar + 7.2 oz oil (initially) + 7.2 oz oil added to make 19.2 oz total.

vinegar is 4.8/19.2 = 0.25

oil is 14.4/19.2 = 0.75

Check my thinking. Check my work.

## Answer This Question

## Related Questions

- Math - 47. For science class, Kyle needs to make a dilute solution of 12 ounces ...
- science - A cylindrical bottle of oil-and-vinegar salad dressing whose volume is...
- Algebra - Kristen wants to make 7.5 ounces of a 25% jasmine essential oil. She ...
- algebra - Kristen wants to make 7.5 ounces of a 25% jasmine essential oil. She ...
- Math - If salad dressing had 1/3 of the mixture was oil, 1/6 of the mixture is ...
- Math - The ratio of oil to vinegar in a certain salad dressing is 8:5. How much ...
- algebra - The ration of oil to vinegar in a certain salad dressing is 8:5. how ...
- Math - A merchant makes two raisin nut mixtures. Each box of mixture A contains ...
- algebra 1 - Madison is making a vinaigrette for her catering service using olive...
- MAth - Your lawnmower uses a gasoline and oil mixture for fuel. For every 2 ...

More Related Questions