Monday

January 26, 2015

January 26, 2015

Posted by **al** on Sunday, November 4, 2007 at 12:17pm.

- calculus -
**drwls**, Sunday, November 4, 2007 at 12:56pmLet x be the brick wall side length and y be the other dimension.

x y = 42 (area requirement)

10 (x+2y) + 30 x = Cost(x,y)

Substitute 42/x for y in the Cost equation to get an equation for cost in terms of x only.

Cost(x) = 10(x + 84/x) + 30x

= 40x + 84/x

Set the derivative equal to 0 and solve fpr x to see where the minimum cost occurs.

**Answer this Question**

**Related Questions**

calculus - A landscape architect wishes to enclose a rectangular garden on one ...

Business Calculus - A rectangular garden of area 480 square feet is to be ...

Calculus - A rectangular garden of area 75 sq ft is to be surrounded on 3 sides ...

math - a landscape architect plans to enclose a 3000 square foot rectangular ...

optimization calcus - A rectangular rose garden will be surrounded by a brick ...

Calculus - ABC Daycare wants to build a fence to enclose a rectangular ...

algebra - Maria’s garden has 24 meters of fence and she wants to fence the ...

Pre-Calculus - A rectangular garden with an area of 250 square meters is to be ...

engineering mathematics 1 - your father wants to fence a rectangular area in ...

Algebra - A rectangular garden is fenced on three sides with wall forming the ...