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April 1, 2015

April 1, 2015

Posted by **al** on Sunday, November 4, 2007 at 12:17pm.

- calculus -
**drwls**, Sunday, November 4, 2007 at 12:56pmLet x be the brick wall side length and y be the other dimension.

x y = 42 (area requirement)

10 (x+2y) + 30 x = Cost(x,y)

Substitute 42/x for y in the Cost equation to get an equation for cost in terms of x only.

Cost(x) = 10(x + 84/x) + 30x

= 40x + 84/x

Set the derivative equal to 0 and solve fpr x to see where the minimum cost occurs.

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