Posted by **al** on Sunday, November 4, 2007 at 12:17pm.

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $30/ft and on the other three sides by a metal fence costing $10/ft. If the area of the garden is 42 square feet, find the dimensions of the garden that minimize the cost.

- calculus -
**drwls**, Sunday, November 4, 2007 at 12:56pm
Let x be the brick wall side length and y be the other dimension.

x y = 42 (area requirement)

10 (x+2y) + 30 x = Cost(x,y)

Substitute 42/x for y in the Cost equation to get an equation for cost in terms of x only.

Cost(x) = 10(x + 84/x) + 30x

= 40x + 84/x

Set the derivative equal to 0 and solve fpr x to see where the minimum cost occurs.

## Answer this Question

## Related Questions

- calculus - A landscape architect wishes to enclose a rectangular garden on one ...
- Business Calculus - A rectangular garden of area 480 square feet is to be ...
- Calculus - A rectangular garden of area 75 sq ft is to be surrounded on 3 sides ...
- math - a landscape architect plans to enclose a 3000 square foot rectangular ...
- Calculus - 1) A rectangular page is to contain 16 square inches of print. The ...
- optimization calcus - A rectangular rose garden will be surrounded by a brick ...
- Calculus - ABC Daycare wants to build a fence to enclose a rectangular ...
- engineering mathematics 1 - your father wants to fence a rectangular area in ...
- algebra - A farmer decides to enclose a rectangular garden, using the side of a ...
- algebra - A farmer decides to enclose a rectangular garden, using the side of a ...