Posted by Lindsay on Sunday, November 4, 2007 at 11:53am.
What you have calculated is the vertical component of the velocity at impact (Vy), not the full speed. The full speed at impact is sqrt (Vx^2 + Vy^2) You need Vx, which is the same as the horizontal velcoity when it was thrown. Vx was the initial speed.
sqrt (Vx^2 + Vy^2) = 5 Vx
Vx^2 + Vy^2 = 25 Vx^2
Vy = sqrt(24)* Vx
Vx = 0.2041 Vy = ?
Ok...explain to me how u obatined the final velocity
The final velocity contains two perpendicular components, horizontal and vertical. Using the pythoreagan theorm,
vf= sqrt(vhoriztal^2+ vvertical*2)
In this case, one knows that Vf=4vhorizontal, and one knows the Vvertialfinal.
Solve for vhorizontal.
But my number was correct, right? 17.714 m/s?
And drwls...where is 0.2041 coming from?
Your number was correct for Vy. You are asked to calculate Vx. You get it by knowing that Vx = sqrt(Vx^2 + Vy^2)
All right. So this is what my equation looks like so far. I need to solve for Vx:
25Vx^2 = 313.786 + Vx^2
Correct?
All right n/m, I finally got the answer. :)
Related Questions
Physics - A ball is thrown horizontally from a height of 16.01 m and hits the ...
Physics - A stone thrown horizontally from a height of 7.8 m hits the ground at ...
Physics - A ball is thrown horizontally from a height of 19.17 m and hits the ...
physics - A ball is thrown horizontally from a height of 18.18 m and hits the ...
Physics - A red ball is thrown down with an initial speed of 1.3 m/s from a ...
physics - A red ball is thrown down with an initial speed of 1.2 m/s from a ...
physics - A ball is thrown from the top of a building upward at an angle of 66 &...
physics - A red ball is thrown down with an initial speed of 1.0 m/s from a ...
physics - A blue ball is thrown upward with an initial speed of 20.6 m/s, from a...
Physics - The ball is thrown vertically upwards from the height of 14.1 meters. ...
For Further Reading
