posted by Dan on .
The equilibrium constant for the reaction of bromine and chlorine to form bromine chloride under certain conditions is 4.7x10-2.
Cl2(g) + Br2(g) --> 2BrCl(g) K= 4.7 x 10-2
What is the equilibrium constant for the following reaction under the same conditions?
1/2 Cl2(g) + 1/2 Br2(g) --> BrCl(g) K=?
k= [BrCl]^2 / [Cl2][Br2]
in the second reaction,
k'= [BrCl2]/[ Cl2]^.5 [Br2]^.5= sqrt k
check my reasoning.