Posted by Chels on Saturday, November 3, 2007 at 3:44pm.
For quadratics, either both roots are real or both are complex. In a special case where the discriminant is zero, there is one root.
In your case, the equation should be written in the ax^2 + bx + c = 0 form, which would be
x^2 -12x + 36 = 0.
discriminant = b^2 - 4ac = 144-144 = 0
So there is only one root.
x = -b/2a = 6, which is a rational number
Related Questions
College Algebra--Still Confused - I have a few problems I need help with and ...
College Algebra - I have a few problems I need help with and also do have ...
math - I HAVE THESE ANSWERS FOR THE PROBLEMS. COULD YOU DOUBLE CHECK PLEASE, ...
math - Could you please solve so I can double check my answers for the practice ...
algebra - Determine the value(s) of k for which x^2+(k-2)x-2k=0 has equal and ...
Algebra HELP:( - Use the discriminant to determine how many real-number ...
Algebra Problem - State the value of the discriminant and the number of real ...
Algebra - Compute the value of the discriminant and give the number of real ...
Algebra - Use the discriminant to determine how many real number solutions the ...
Algebra II - Which describes the number and type of roots of the equation x^2 -...
For Further Reading