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January 25, 2015

January 25, 2015

Posted by **Chels** on Saturday, November 3, 2007 at 3:44pm.

1 real, irrational

2 real, rational

no real

1 real, rational

- Algebra 2(quadratic) -
**drwls**, Saturday, November 3, 2007 at 4:08pmFor quadratics, either both roots are real or both are complex. In a special case where the discriminant is zero, there is one root.

In your case, the equation should be written in the ax^2 + bx + c = 0 form, which would be

x^2 -12x + 36 = 0.

discriminant = b^2 - 4ac = 144-144 = 0

So there is only one root.

x = -b/2a = 6, which is a rational number

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