Posted by **fred** on Saturday, November 3, 2007 at 12:17am.

A 3700 kg statue is placed on top of a cylindrical concrete (Y = 2.3 1010 N/m2) stand. The stand has a cross-sectional area of 7.2 10-2 m2 and a height of 2.0 m. By how much does the statue compress the stand?

- Physics -
**drwls**, Saturday, November 3, 2007 at 12:28am
They give you Young's moduls of the concrete, Y = 2.3*10^10 N/m^2

The pedestal area is A = 7.2*10^-2 m^2

Use the elastic law that

stress = (strain)*Y

In this case,

strain = compression/length

Therefore

compression = Length*strain

= Length*stress/Y

= Length *(weight)/[(area)*Y]

Don't forget that weight = M g, so

compression = L M g/[(area)*Y]

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