Posted by **Lindsay** on Friday, November 2, 2007 at 7:07pm.

Salmon, swimming up the Fraser river to their spawning grounds, leap over all sorts of obstacles. The unofficial salmon-altitude record is an amazing 3.58 m jump. Assuming the fish took off at 45.0°, what was its speed on emerging from the water? Ignore friction.

This problem is driving me CRAZY. I've tried this many times, but I have a feeling I'm making it a lot harder than it really is. Could someone tell me which equations I need to use?

- Physics -
**drwls**, Friday, November 2, 2007 at 8:42pm
Let V be the initial velocity leaving the water. The vertical component of the velocity, V sin 45, must be enough to let the salmon reach a height of h = 3.58 m

Maximum altitude h is reached when

V sin 45 = g T

The maximum height reached is then

h = (1/2) V sin 45 T

= (1/2) [V sin 45]^2/g = (1/4)V^2/g

V =sqrt (4 g h) = 2 sqrt (g h)

- Physics -
**Lindsay**, Friday, November 2, 2007 at 11:20pm
THANK YOU!

- Physics -
**drwls**, Saturday, November 3, 2007 at 1:06am
v = 11.8 m/s

That is faster than the fastest human can run horizontally (10 m/s)!

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