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April 27, 2015

Homework Help: Calculus I

Posted by Mandy on Friday, November 2, 2007 at 7:52am.

Find the point on the curve y=x^2 closest to point (0,1)

Here's what I have:

Sqrt {(x-0)^2 + ((x^2)-1)}

Sqrt {((x^2) + (x^2)-1}

d= sqrt (x^4)-1
y= (x^4)-1
Fprime(x) = 4x^3

Domain = ARN

Critical Number x= 0

Any help or comments would help alot. Thanks!

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