Posted by **ALGRBRA** on Thursday, November 1, 2007 at 1:06am.

I have put together the math in words, please help me show the work in a math format. Info below Note 1,2,3

To find the population growth rate subtract the population of 2006 from 2007. Divide that answer by the 2006 population.

Australia’s growth rate from 2006 to 2007 was 0.67% per year.

1). 20,743,300 subtract 20,605,500 divided by 20,605,500 which equal the Population growth which is .00668 = 0.67%

2). 20,743,300 times .0067 equals the amount of growth of the population in 2007 which equals 138981

3). Find the approximate population which is 138981 + population of 2007 (which is 20,743,300) = 2008 population which is 20,882,281( 26 January 2008)

Using Australia data in the reference

20,882,281( 26 January 2008)

20,743,300 (26 January 2007)

20,605,500 (26 January 2006)

20,171,300 (26 January 2005)

- Math -- not "Vision/Help me" -
**Writeacher**, Thursday, November 1, 2007 at 8:01am
Math assistance needed here.

- Vision/Help me -
**Reiny**, Thursday, November 1, 2007 at 8:51am
The way I understand it is that ALGRBRA wants to have the steps above labeled 1) 2) and 3) in mathematical statements.

So....

1): Population growth = (20743300 - 20605500)/20605500

= .0066875

= .67%

2): amount of growth of the population in 2007 = 20743300(.67%)

= 20743300(.0067)

=138980

3): approximate population in 2008 = 138981 + 20743300

=20882281

BTW, all your populations were expressed in hundreds, so I would not leave my answers in the number form of your given data.

I would state the 2008 population as

20,882,300

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