Sunday

December 21, 2014

December 21, 2014

Posted by **sara** on Wednesday, October 31, 2007 at 10:34pm.

y=2cotx+sec3x+cscX

find d^2/dx^2 for 1+y=x+xy

- derivatives -
**Reiny**, Wednesday, October 31, 2007 at 10:54pmThe derivatives of these trig functions should be right there in your Calculus text.

for the second of your questions, I will use y' for the first derivative and y" for the second derivative i.e. y'= dy/dx

1+y=x+xy so

y' = 1 + y + xy'

y'(1-x) = 1+y

y' = (1+y)/(1-x)

y" = [(1-x)y' - (1+y)(-1)]/((1-x)^2)

=[(1+y) + (1+y)]/((1-x)^2) after I replaced y'

=(2+2y)/((1-x)^2)

**Answer this Question**

**Related Questions**

Calculus (Derivatives) - Using the product rule, find the derivative of the ...

Calculus - derivatives - Okay, I want to find the derivative of (x^x)^(x^x)... ...

math - I studied derivatives before, but kind of forgot them all, is there a ...

calculus - Differentiate both sides of the double angle identify sin 2x= 2 sin x...

Calculus derivatives - f(a) = a + √a (a) Find the derivative of the ...

Derivatives- Math - Can someone explain how to find the derivative of : 1. y= 5...

Applied Calculus - Find the first and second derivative of the function: x/(7x+...

math - how do i ,prove: 1/(sec x-1) + 1/(sec x-1)= 2cotx cscx

math - how do i ,prove: 1/(sec x-1) + 1/(sec x-1)= 2cotx cscx

Calculus (Derivatives) - What is the derivative of the this functon? g(x) = -500...