Posted by **Tammy** on Wednesday, October 31, 2007 at 8:23pm.

A bike wheel rotates uniformly through 2 revolutions in 3 seconds.

a) what is the period of the wheel's rotation?

T=3rev/2s=1.5s

b) what is the frequency of the wheel's rotation? (in Hertz)

f=1/T

=1/1.5

=.666Hz

c) what is the angular speed of the wheel(provide answer in degrees, radians and revolutions)

How would I figure out part c? also did I do a) and b) correctly?

- Physics -
**bobpursley**, Wednesday, October 31, 2007 at 8:30pm
part c: doesn't it rotate 2Pi in one period?

a: How did you get it 3 rev per 2 seconds? that is not given.

B, of course is wrong because of period is wrong.

- Physics -
**Tammy**, Wednesday, October 31, 2007 at 8:58pm
Well isn't T = to the time of one revolution? So I took 3rev/2s to get 1.5s

- Physics -
**bobpursley**, Thursday, November 1, 2007 at 8:14am
Tammmy. IT did not complete 3 revolutions. Reread the problem.

- Physics -
**Mak**, Saturday, October 27, 2012 at 1:58pm
Bob is right, it did not complete 3 revolutions, but the answer for a) is still correct, for the wrong reason.

Wheel completes 2 revolutions in 3 seconds. Period is amt of time to complete 1 revolution. Think of it as a distance problem.

Distance (# of revolutions) = Rate (revolutions/second) * Time (seconds)

So 1 revolution = (2 revolutions per 3 seconds) * Time

Time = (1 rev)/(2 revs/3 seconds) = 3/2 seconds, or 1.5 seconds

For part C, just divide the distance around the circle by the period 1.5s

i) 360 degrees/1.5 sec = 240 degrees/sec

ii) 2pi radians/1.5 sec = (4/3)pi rad/sec

iii) 1 revolution/1.5 sec = 2/3 rev/sec

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