Posted by **Tammy** on Wednesday, October 31, 2007 at 8:15pm.

A .5kg ball on the end of a string is revolving uniformly in ahorizontal circle of radius 1m. The ball makes 2 revolustion in a second.

a) determine the linear (tangential) speed of the ball.

For this part of the question would I do this:

v=d/t

=1m/.5s

=2m/s

b)determine the ball's centripetal acceleration

a_c=v^2/r

=2m/s^2/1

=4m/s^2

c)determine the force a person must exert on the opposite end of the string.

F_c=mv^2/r

=.5kg(2m/s)^2/1

=2N

Is this correct? The only thing i'm not too sure about is part a). Thanks in advance for your help.

- physics -
**bobpursley**, Wednesday, October 31, 2007 at 8:28pm
The distance around the circle is 2PI*radius, v= distance/time You have distance equal to radius.

The centripetal force is indeed v^2/r, your numbers are of course wrong.

part A messes up part b, c.

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