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November 27, 2014

November 27, 2014

Posted by **Monte'** on Tuesday, October 30, 2007 at 7:51pm.

8x^2-10x+3

15X^2-x-2

8X^2-18X-5

2x^2-5x-88

3x^2+43x-30

3x^2+7x-2

10^2-89x+156

4x^2+11x+13

3x^2-42x+147

5x^2-20x+20

- Math -
**drwls**, Wednesday, October 31, 2007 at 2:28amBreak the coefficeint of the x^2 term and the constant both into prime number factors (a*b) and (c*d), and then try various combinations of (ax+c)(bx+d) until you find one that works.

For 8x^2-10x+3, choose 4 and 2 for the factors of 8 and 3 and 1 for the factors of 3.

(4x - 3)(2x - 1) works!

The pair of minus signs before 3 and 1 is needed to make the 3 positive and -10 negative in the final product

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