Posted by Monte' on Tuesday, October 30, 2007 at 7:51pm.
Break the coefficeint of the x^2 term and the constant both into prime number factors (a*b) and (c*d), and then try various combinations of (ax+c)(bx+d) until you find one that works.
For 8x^2-10x+3, choose 4 and 2 for the factors of 8 and 3 and 1 for the factors of 3.
(4x - 3)(2x - 1) works!
The pair of minus signs before 3 and 1 is needed to make the 3 positive and -10 negative in the final product
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