Posted by John on Tuesday, October 30, 2007 at 1:18pm.
On the first, factor 42 out of the second paren.
7x(x+1)+ 42(x+1)
(x+1)(7x+42)
now factor 7 out of the second..
7(x+1)(x+6)
Onthe last, factor the common factor x^8*y out
yx^8[(xy)^2 -4xy -21]
The last term factors to (xy-7)(xy+3)
Solution for No.1
7x^2 + 49x + 42
7x^2 + 7x + 42x + 42
(7x^2 + 7x) + (42x + 42)
[7x(x+1)+ 42(x+1)]
(7x+42)(x+1)
7(x+6)(x+1)
Solution for No.2
x^10y^3 - 4x^9y^2 - 21x^8y
x^8y (x^2y^2 - 4xy - 21)
x^8y (xy-7)(xy+3)
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