On the first, factor 42 out of the second paren.
now factor 7 out of the second..
Onthe last, factor the common factor x^8*y out
yx^8[(xy)^2 -4xy -21]
The last term factors to (xy-7)(xy+3)
Solution for No.1
7x^2 + 49x + 42
7x^2 + 7x + 42x + 42
(7x^2 + 7x) + (42x + 42)
Solution for No.2
x^10y^3 - 4x^9y^2 - 21x^8y
x^8y (x^2y^2 - 4xy - 21)
Answer this Question
algebra - I need to factor (my last post was incorrect) 24x^2 + 42x + 15
Pre Calculus - factor completely 1. x^3-9x^2 2. 36x^6-49x^4
Algebra - Andrew factored the expression 28x^3-42x^2+35x as 7x(4x^2+6x-5). But ...
math - I need help with these two problems please. Completely factor the ...
Algebra 1 - factor out the greatest common factor. 7x^4-49x^3+14x^2=7x^2 Is this...
Quick math help - Can someone please check my math Hw? Thank you!! Solve each ...
Algebra 2 - what is the opposite of 49x^2y A. 49x^-2y b. -49x^2y c. 1/49x^2y d...
Algebra HELP! - 6(7x - 5) = - 114 HELP!!!! distribute the 6 to the 7x and 5. ...
mat117/algebra - factor each polynomial completely. to begin, state which method...
algebra - Factor 24^2 + 42x + 15