Posted by Kim on Tuesday, October 30, 2007 at 11:01am.
For d/dx(partial)of (3x + 2y)^1/2, just treat y as a constant and use the usual rules. In this case, use the chain rule and let u = 3x + 2y
df/dx = df/du*du/dx
d/dx(partial)of (3x + 2y)^1/2
=(1/2)(3x + 2y)^-1/2 * 3
= (3/2)(3x + 2y)^-1/2
k tnx for ur help
-5(3x+2)
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