Posted by Alan on Monday, October 29, 2007 at 5:02pm.
A train left Podunk and traveled north at 75 Km/h. Two hours later, another train left Podunk and traveled in the same direction at 100 km/h. How many hours had the first train traveled when the second train overtook it?

Algebra II  Ms. Sue, Monday, October 29, 2007 at 5:14pm
You can solve it algebraically or you can set up a chart:
First train:
1 hr: 75 mi
2 hr: 150 mi
3 hr: 225 mi
 Continue this chart
Second train:
1 hr: 100 mi
2 hr: 200 mi
3 hr: 300 mi
 Continue this chart.
Compare the charts to see when they've both traveled the same distance, but the second train reached it in two hours less.

Algebra II  DrBob222, Monday, October 29, 2007 at 5:18pm
distance = rate x time
A train rate = 75 km/hr
B train rate = 100 km/hr
distance traveled by A train =
75 x (t+2 hrs)
distance traveled by B train =
100 x t
Distance is the same so set them equal to each other.
75(t+2) = 100t
solve for t = time.

Algebra II  nicole, Friday, March 30, 2012 at 2:21pm
Use the matrix method to solve:
x + 4y = 8
2x + y = 9
x = a0
y = a1

Algebra l  sam pucket, Tuesday, October 7, 2014 at 10:21pm
your butt
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