Algebra II
posted by Alan on .
A train left Podunk and traveled north at 75 Km/h. Two hours later, another train left Podunk and traveled in the same direction at 100 km/h. How many hours had the first train traveled when the second train overtook it?

You can solve it algebraically or you can set up a chart:
First train:
1 hr: 75 mi
2 hr: 150 mi
3 hr: 225 mi
 Continue this chart
Second train:
1 hr: 100 mi
2 hr: 200 mi
3 hr: 300 mi
 Continue this chart.
Compare the charts to see when they've both traveled the same distance, but the second train reached it in two hours less. 
i needhelp with solving systems of equetions algebrically

distance = rate x time
A train rate = 75 km/hr
B train rate = 100 km/hr
distance traveled by A train =
75 x (t+2 hrs)
distance traveled by B train =
100 x t
Distance is the same so set them equal to each other.
75(t+2) = 100t
solve for t = time. 
Use the matrix method to solve:
x + 4y = 8
2x + y = 9
x = a0
y = a1 
your butt