Posted by bob on Monday, October 29, 2007 at 9:44am.
1. 4x^2-13x -12 = 0
Playing around a bit with the pairs 4&3 and 6&2 as the constants, I get
(4x + 3)(x -4) = 0
That makes the roots x=-3/4 and 4
2. x^2 = -42/5
There are two imaginary roots that have an "i" (sqrt(-1) factor
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