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September 20, 2014

September 20, 2014

Posted by **bob** on Monday, October 29, 2007 at 9:44am.

I need to solve this problem by factoring or using the quadtratic formula. I am stuck when using the quadtratic formula method. Please advise how to do this.

2. 5x^2+42=0

How many roots exist in this equation and what type are they?

- math -
**drwls**, Monday, October 29, 2007 at 10:06am1. 4x^2-13x -12 = 0

Playing around a bit with the pairs 4&3 and 6&2 as the constants, I get

(4x + 3)(x -4) = 0

That makes the roots x=-3/4 and 4

2. x^2 = -42/5

There are two imaginary roots that have an "i" (sqrt(-1) factor

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