Posted by K on Sunday, October 28, 2007 at 8:57pm.
#1. P1V2 = P2V2
#2. P1/T1 = P2/T2. Don't forget to change T to Kevin.
#3. From 1 and 2 you should have enough information to calculate n, the number of mols. Then n = grams/atomic mass. Calculate atomic mass.
for Part 1:
would the P2 just be 0.454 atm then?
I went: P1*V1=P2*V2
So...1atm*1L/2.20L = P2= 0.454atm??
ok...I tried my answer...I got the first part correct..it was actually 0.455atm.
the only prob left is: do I just add the variables? or which ones do I take into account?
n=RT/PV...or should I be using:
well...I managed to use the correct equation: M=mRt/PV...& the answer came to Ar.
Thank you very much!!
OR, you could have done it in two steps.
PV = nRT
n = 0.0416 mols
Then mols = g/atomic mass and rearrange to atomic mass= g/mols = 1.66/0.0416 = 39.9 = Ar. I prefer the two step method because it makes the first equation a little easier to solve but this's just my preference.
Try this formula
How did Dr.Bob find n = 0.0416 mols ?
Where did 0.0416 moles come from?
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