Tuesday

March 31, 2015

March 31, 2015

Posted by **julie** on Sunday, October 28, 2007 at 8:44pm.

the critical numbers i got was x=0,-2.59, and 3.09

the absolute minimum is f(0)=-1

what is the absolute maximum:

is it both f(-4)=(f(4))=.6?

or can there only be one

- absolute maximum -
**drwls**, Monday, October 29, 2007 at 12:04amThe absolute maximum must occur where the deriviative is zero. But you also have to use othe tests to show that it not a minimum or only a relative maximum.

The derivative is [(x^2+4)(2x) - (x^2-4)(2x)]/(x^2+4)^2

=16 x/(x^2+4)^2

That only equals zero when x = 0. That happens to be the absolute minimum. There is no absolute maximum. The function approaches +1 as x goes to plus or minus infinity.

**Answer this Question**

**Related Questions**

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum ...

Calculus (pleas help!!!) - Find the absolute maximum and absolute minimum values...

Calculus - Find the absolute maximum and absolute minimum values of the function...

calculus - 2) Let g(s)= t(4−t)^1/2 on the interval [0,2]. Find the ...

Caluclus - Find the absolute maximum and absolute minimum of f on the interval...

Calc 3 - If a function of one variable is continuous on an interval and has only...

Calculus - Find the absolute extrema of the function on the interval [2, 9]. (...

Calculus - Let f(t)=t\sqrt{4-t} on the interval [-1,3]. Find the absolute ...

Calculus - Find the absolute extrema of the function. (Round your answer to ...

Calculus - Find the absolute extrema of the function. (Round your answer to ...