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April 17, 2014

Posted by **anonymous** on Sunday, October 28, 2007 at 10:24am.

Let t=time=5 hours

Let 18t= first ship=90

Let 23t= second ship=115

18t+23t+60=265

41t+60=265

41t=205

t=5

Answer= 5+3= 8:00PM

Is this all correct? My main problem is with the Let statements. Are there only those three? Are they right? How do I label 90 and 115? (90 what, 115 what?)

Thanks Very much in advance for any help.

- Algebra -
**tchrwill**, Sunday, October 28, 2007 at 2:41pmSubjects

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At 3PM, two ships started sailing toward each other from ports which were 265 miles apart at average rates of 18 and 23 miles per hour. At what time were the ships still 60 miles apart?

Let t=time=5 hours

Let 18t= first ship=90

Let 23t= second ship=115

18t+23t+60=265

41t+60=265

41t=205

t=5

Answer= 5+3= 8:00PM

Is this all correct? My main problem is with the Let statements. Are there only those three? Are they right? How do I label 90 and 115? (90 what, 115 what?)

Thanks Very much in advance for any help.

8 PM it is.

Alternatively, the two ships are closing the gap between one another at the rate of 23 + 18 = 41mph.

How long does it take for the two ships to be 60 miles apart?

t = (265 - 60)/41 = 5 hours.

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