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October 1, 2014

October 1, 2014

Posted by **anonymous** on Saturday, October 27, 2007 at 11:56am.

- algebra -
**drwls**, Saturday, October 27, 2007 at 12:02pmThe distance between them increases at a rate of 5 miles per hour.

Using that relative rate r,

r t = 5 t = 30

t = 6 hours

- algebra -
**Reiny**, Saturday, October 27, 2007 at 12:03pmFollow the example of the problem I solved for you two posting below this.

The two problems are very similar.

Let me know what you got.

- algebra -
**anonymous**, Saturday, October 27, 2007 at 12:39pmi don't get how to start on this one since it doesn't give how far apart the towns are. Well, there;s only one town- whatdo i do???

- algebra -
**Reiny**, Saturday, October 27, 2007 at 12:43pmYou don't have to know that, you know they are 30 miles apart.

So if you let the time be t hours, then the faster has traveled 45t miles, and the slower has traveled 40 t miles

The difference in the distance traveled is 30 miles, so....

45t - 40t = 30

5t=30

notice we now have the same equation that drwls obtained by simple common sense.

- algebra -

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