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August 29, 2014

August 29, 2014

Posted by **anonymous** on Saturday, October 27, 2007 at 11:50am.

*Again, I;m having a real bad day; please walk me through this.*

- algebra -
**Reiny**, Saturday, October 27, 2007 at 12:00pmWhen they are 60 miles apart, let the time they have traveled be t hours.

So the first one went 13t miles, and the second went 23t miles.

then 13t + 23t + 60 = 265

36t = 205

t = 5.6944 hours

which is 5 hours and about 42 minutes

so they were 60 miles apart at 8:42 pm

- algebra -
**anonymous**, Saturday, October 27, 2007 at 12:08pmThanks!

- algebra -
**anonymous**, Saturday, October 27, 2007 at 12:34pmHang on, it should be 18t not 13t, so then I got t=5, so the answer would then be 8PM, right? Should there be only the one let statement though? Cuold I put 3 lETS?;

LET t=time=5hours

let 18t=mph of 1st ship

let 23t=mph of 2nd ship?

- algebra -
- algebra -
**Reiny**, Saturday, October 27, 2007 at 12:45pmYou are right, let's blame it on poor eyesight.

But it looks like you can now do these kind of questions.

- algebra -
**anonymous**, Saturday, October 27, 2007 at 1:00pmFor the let statements- do they look correct?

- algebra -
- algebra -
**Arnisha Gray**, Wednesday, September 19, 2012 at 8:56amIf one train is moving at 174 miles per hour and another train is moving in the opposite direction at 112 miles per hour, at what rate are the trains moving apart?

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