Posted by **anonymous** on Saturday, October 27, 2007 at 11:41am.

The base of an isosceles triangle and one of its legs have lengths that have consecutive integers. The leg is longer than the base. The perimeter of the triangle is 20. Find the length of each side of the triangle.

*Please help me- I am having a really bad day. Thank you.*

- algebra -
**Reiny**, Saturday, October 27, 2007 at 11:53am
Let the base be x units long.

"Consecutive integers" are one apart, so if the first one is x then the next one must be x+1.

So the other two sides must be x+1 each.

Since perimeter is the sum of the 3 sides...

x + x+1 x + x+1 = 20

3x + 2 = 20

3x=18

x=6

So the base is 6 and each of the other two sides is 7

check: 6 and 7 are consecutive integers

6+7+7 = 20

- algebra -
**Reiny**, Saturday, October 27, 2007 at 12:06pm
It was clearly a typo

looking at the line that follows should have made it obvious.

this is what it should have been putting the sides in brackets

(x) + (x+1) + (x+1) = 20

- algebra -
**anonymous**, Saturday, October 27, 2007 at 12:12pm
ok I get it. I got x= 6 now i can go from there. Thanjs much for all your help!

- algebra -
**Anonymous**, Tuesday, February 16, 2016 at 10:28am
i don't know the answer

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