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October 24, 2014

October 24, 2014

Posted by **Amanda** on Saturday, October 27, 2007 at 1:14am.

A developer wants to build homes on a rectangular plot of land 4 kilometers long and 3 kilometers wide. In this part of the city, regulations require a greenbelt of uniform width along two adjacent sides. The greenbelt must be 10 times the area of the development. Find the width of the greenbelt.

- Precalculus/Trigonometry -
**drwls**, Saturday, October 27, 2007 at 2:25amLet the greenbelt width be x. The developed area is (5-x)*(4-x). The greenbelt area is 5x + (4-x)x = 9x - x^2

The requirement is

9x - x^2 = 10 *(x^2 -9x +20)

11 x^2 -99 x +200 = 0

x^2 - 9x + 200/11 = 0

The labeled diagram is one rectangle nested inside a larger triangle with one pair of corners aligned, and a gap of x along the two perpendicular opposite sides

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