Posted by **Mary** on Friday, October 26, 2007 at 11:28pm.

A converging lens has a focal length of 0.060 m. An object is located 0.020 m to the left of this lens. A second converging lens has the same focal length as the first one and is located 0.100 m to the right of it. Relative to the second lens, where is the final image located?

- Physic please help! -
**drwls**, Saturday, October 27, 2007 at 2:37am
The image formed by the first lens is virtual, and is located at X given by

1/0.02 + 1/X = 1/0.06

1/X = -33.33

X = -0.03

The minus sign indicates it is 0.03 m to the LEFT of lens 1. That becomes the object position for the second lens, and it is 0.13 m to the left of lens 2. For the location of the final image, solve

1/0.13 + 1/Di = 1/0.06

Do is the image distance, measured to the right of lens 2.

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