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October 25, 2014

October 25, 2014

Posted by **Dick** on Friday, October 26, 2007 at 2:54pm.

: Suppose you have collected the data shown below for the circuit in Figure 1.

Voltage is measured across the

resistor. Current is measured

through the resistor. The

exact value of the resistor is

100 Ω.

Figure 1.

DESCRIBE THE MEASURED QUANTITIES:

“x” Electric Current in Amperes .

“y” Voltage in Volts .

DATA:

TRIAL “x” (units) “y” (units) k = y/x

1 .041 A 4.0 V

2 .083 A 8.2 V

3 .127 A 12.3 V

4 .162 A. 16.0 V

5 .200 A 21.0 V

EQUATION OF DATA (USING FORM y = mx + b): .

ACCEPTED VALUE FOR k: .

ACCURACY: AVERAGE k – ACCEPTED k x 100% = .

ACCEPTED k

PRECISION: HIGHEST VALUE OF k x 100% = .

LOWEST VALUE OF k

.

ACCURACY: AVERAGE k – ACCEPTED k x 100% = .

ACCEPTED k

PRECISION: HIGHEST VALUE OF k x 100% = .

LOWEST VALUE OF k

- Physics -
**Dick**, Friday, October 26, 2007 at 2:55pmTRIAL “x” (units) “y” (units) k = y/x

1 .041 A 4.0 V

2 .083 A 8.2 V

3 .127 A 12.3 V

4 .162 A. 16.0 V

5 .200 A 21.0 V

- Physics -
**Dick**, Friday, October 26, 2007 at 2:57pm“x”(units)“y” (units)k = y/x

1.041 A 4.0 V

2.083 A 8.2 V

3.127 A 12.3 V

4.162 A.16.0 V

5.200 A 21.0 V

- Physics -
**Dick**, Friday, October 26, 2007 at 2:57pmNEVER MIND I CANT Get it to post

- Physics -

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