Posted by Dick on Friday, October 26, 2007 at 2:54pm.
How do i do this ? ? ?
: Suppose you have collected the data shown below for the circuit in Figure 1.
Voltage is measured across the
resistor. Current is measured
through the resistor. The
exact value of the resistor is
100 Ω.
Figure 1.
DESCRIBE THE MEASURED QUANTITIES:
“x” Electric Current in Amperes .
“y” Voltage in Volts .
DATA:
TRIAL “x” (units) “y” (units) k = y/x
1 .041 A 4.0 V
2 .083 A 8.2 V
3 .127 A 12.3 V
4 .162 A. 16.0 V
5 .200 A 21.0 V
EQUATION OF DATA (USING FORM y = mx + b): .
ACCEPTED VALUE FOR k: .
ACCURACY: AVERAGE k – ACCEPTED k x 100% = .
ACCEPTED k
PRECISION: HIGHEST VALUE OF k x 100% = .
LOWEST VALUE OF k
.
ACCURACY: AVERAGE k – ACCEPTED k x 100% = .
ACCEPTED k
PRECISION: HIGHEST VALUE OF k x 100% = .
LOWEST VALUE OF k

Physics  Dick, Friday, October 26, 2007 at 2:55pm
TRIAL “x” (units) “y” (units) k = y/x
1 .041 A 4.0 V
2 .083 A 8.2 V
3 .127 A 12.3 V
4 .162 A. 16.0 V
5 .200 A 21.0 V

Physics  Dick, Friday, October 26, 2007 at 2:57pm
“x”(units)“y” (units)k = y/x
1.041 A 4.0 V
2.083 A 8.2 V
3.127 A 12.3 V
4.162 A.16.0 V
5.200 A 21.0 V
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