Posted by **Anonymous** on Friday, October 26, 2007 at 12:14am.

An automobile computer gives a digital readout of fuel consumption in gallons per hous. During a trip, a passenger recorded the fuel consumption every 5 minutes for a full hour of travel.

time: 0 / gal/h: 2.5

time: 5 / gal/h: 2.4

time: 10 / gal/h: 2.3

time: 15 / gal/h: 2.4

time: 20 / gal/h: 2.4

time: 25 / gal/h: 2.5

time: 30 / gal/h: 2.6

time: 35 / gal/h: 2.5

time: 40 / gal/h: 2.4

time: 45 / gal/h: 2.3

time: 50 / gal/h: 2.4

time: 55 / gal/h: 2.4

time: 60 / gal/h: 2.3

(a) Use the Trapezoidal Rule to approximate the total fuel consumption during the hour.

(b) If the automobile covered 60 miles in the hour, what was its fuel efficiency (in miles per gallon) for that portion of that trip.

Answer: (a) 2.42 gal (b)24.83mpg

- calculus -
**drwls**, Friday, October 26, 2007 at 1:47am
a)The trapezoidal rule is a way of doing numberical integration. Add up the middle 11 gal/h entires and add hlad of the first and last entries; then multiply by the time interval between entries, 0.0833 hours.

b) Divide 60 miles by the 2.42 gallons consumed. You should show only three significant figures

- calculus -
**Anonymous**, Friday, October 26, 2007 at 2:21am
what do you mean add "hlad"?

- calculus -
**drwls**, Friday, October 26, 2007 at 2:27am
Sorry about the typo. That word should be "half"

- calculus -
**fool**, Sunday, September 4, 2011 at 8:14pm
I need a better more indepth answer

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