calculus
posted by Anonymous on .
An automobile computer gives a digital readout of fuel consumption in gallons per hous. During a trip, a passenger recorded the fuel consumption every 5 minutes for a full hour of travel.
time: 0 / gal/h: 2.5
time: 5 / gal/h: 2.4
time: 10 / gal/h: 2.3
time: 15 / gal/h: 2.4
time: 20 / gal/h: 2.4
time: 25 / gal/h: 2.5
time: 30 / gal/h: 2.6
time: 35 / gal/h: 2.5
time: 40 / gal/h: 2.4
time: 45 / gal/h: 2.3
time: 50 / gal/h: 2.4
time: 55 / gal/h: 2.4
time: 60 / gal/h: 2.3
(a) Use the Trapezoidal Rule to approximate the total fuel consumption during the hour.
(b) If the automobile covered 60 miles in the hour, what was its fuel efficiency (in miles per gallon) for that portion of that trip.
Answer: (a) 2.42 gal (b)24.83mpg

a)The trapezoidal rule is a way of doing numberical integration. Add up the middle 11 gal/h entires and add hlad of the first and last entries; then multiply by the time interval between entries, 0.0833 hours.
b) Divide 60 miles by the 2.42 gallons consumed. You should show only three significant figures 
what do you mean add "hlad"?

Sorry about the typo. That word should be "half"

I need a better more indepth answer