Friday
March 24, 2017

Post a New Question

Posted by on Thursday, October 25, 2007 at 10:06pm.

please help me with the following:

The value of a particular investment follows a pattern of exponential growth. In the year 2000, you invested money in a money market account. The value of your investment t years after 2000 is given by the exponential growth model a=3000e^0.053t When will the account be worth $5097?

  • Algebra word problem - , Thursday, October 25, 2007 at 10:26pm

    Set 3000e^0.053t = $5097
    e^0.053t = 5097/3000 = 1.699
    Take the natural log of both sides
    .053 t = 0.53
    t = _?_ years

  • Algebra word problem - , Thursday, October 25, 2007 at 11:12pm

    I got 10 years, but my answer choices are: a. 2010, b.2011, c.2009, d. 2012.
    And I don't understand how you took the natural log of both sides?

  • Algebra word problem - , Thursday, October 25, 2007 at 11:25pm

    You add t to the year 2000 in this case, so the answer is a.
    Taking the natural log (to base e) was in my case done with a hand calculator. The natural log of e^x is x.

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question