Posted by Soph. on Thursday, October 25, 2007 at 10:06pm.
Set 3000e^0.053t = $5097
e^0.053t = 5097/3000 = 1.699
Take the natural log of both sides
.053 t = 0.53
t = _?_ years
I got 10 years, but my answer choices are: a. 2010, b.2011, c.2009, d. 2012.
And I dont understand how you took the natural log of both sides?
You add t to the year 2000 in this case, so the answer is a.
Taking the natural log (to base e) was in my case done with a hand calculator. The natural log of e^x is x.
Related Questions
math - The following graph shows the growth of the median home value in a ...
math - algebra - f(t) is an exponential function with f(0) = 200 and f(3) = 2000...
math - algebra - f(t) is an exponential function with f(0) = 200 and f(3) = 2000...
math - algebra - f(t) is an exponential function with f(0) = 200 and f(3) = 2000...
math - im not sure what a exponential growth pattern is and I need to find a ...
Algebra - 1) The following graphs shows the growth of the median home value in a...
algebra 2 - Solve the problem. The growth in the population of a certain rodent ...
algebra - In 1998, the population of a given country was 37 million, and the ...
Algebra - Wk 6 Sec 12.7 #24 World population growth In 2008 the world population...
College Mathematics - Guys, could you please help me with this problem? I'm ...
For Further Reading