Posted by **david** on Thursday, October 25, 2007 at 8:49pm.

A particle moves with constant speed of 3m/sec along path y=3x^2

What is the acceleration of the particle at x=1.5m?

- physics -
**drwls**, Thursday, October 25, 2007 at 11:43pm
Since the speed is constant, the acceleration must be caused by the change in direction. The angle of the trajectory to the x axis is

theta = arctan (dy/dx) = arctan (6x)

When x = 1.5, theta = arctan 9 = 83.66 degrees

The acceleration will be

(speed)x d(theta)/dt

= (speed)* d(theta)/dx* dx/dt

Take it from there.

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