Wednesday

April 16, 2014

April 16, 2014

Posted by **david** on Thursday, October 25, 2007 at 8:49pm.

What is the acceleration of the particle at x=1.5m?

- physics -
**drwls**, Thursday, October 25, 2007 at 11:43pmSince the speed is constant, the acceleration must be caused by the change in direction. The angle of the trajectory to the x axis is

theta = arctan (dy/dx) = arctan (6x)

When x = 1.5, theta = arctan 9 = 83.66 degrees

The acceleration will be

(speed)x d(theta)/dt

= (speed)* d(theta)/dx* dx/dt

Take it from there.

**Related Questions**

math - A particle moves with constant speed of 3m/sec along path y=3x^2 What is ...

calculus - a particle moves along a number line measured in cm so that its ...

physics help - The magnitude of the velocity of a particle which starts from ...

physics help - The magnitude of the velocity of a particle which starts from ...

Physics - A 0.500 kg particle moves in a circle of R=0.0150 m at constant speed...

math - Which three options are true about motion in a straight line. A. A ...

Physics - A particle moves along a circular path over a horizontal xy coordinate...

physics - A particle moves along a circular path over a horizontal xy coordinate...

Physics - A particle starts from the origin at t = 0 and moves along the ...

Physics/Math - At time t1 = 2.00 s, the acceleration of a particle in ...