The product of two consective positive even intergers is 440. Would they be 20 and 22?
let the first integer be x, then the next even integer is x+2
translating your English into Math...
x(x+2)=440
x^2 + 2x - 440 = 0
(x-20)(x+22)=0
so x=20 or x=-22
case 1, the two numbers are 20 and 22 (you had that) or
case 2, the two integers are -22 and -20
oops, disregard the negative answers, I did not read the "positive" integer part
The product of two consective positive even intergers is 440. Would they be 20 and 22?
The two consecutive even integers would be the two on both sides of the square root of 440. The square root of 440 is 20.976 thereby making the two even integers 20 and 22.
one positive interger is 5 less than 3 times another and their product is 78 what are the two intergers?
To find the consecutive positive even integers that multiply to give 440, we can set up an equation.
Let's assume the first even integer is represented by x. Since consecutive even integers differ by 2, the second even integer can be represented by (x + 2).
The equation we set up is:
x * (x + 2) = 440
Expanding the equation:
x^2 + 2x = 440
Rearranging the equation to make it quadratic:
x^2 + 2x - 440 = 0
Now we can solve this quadratic equation to find the value of x, which will give us the first even integer.
We can use factoring, completing the square, or using the quadratic formula to solve this equation. Let's use factoring:
(x + 22)(x - 20) = 0
Setting each factor equal to zero:
x + 22 = 0 or x - 20 = 0
Solving for x:
x = -22 or x = 20
Since we are looking for positive even integers, we can discard the negative solution.
Therefore, the first positive even integer is x = 20. And the second even integer is (20 + 2) = 22.
Hence, the consecutive positive even integers that multiply to give 440 are indeed 20 and 22.