Posted by **Kay** on Wednesday, October 24, 2007 at 11:00am.

Solve the following interval

0<_ (less than or equal to)0(Theta)<2pi:

1. sin0(theta) + sin2 0(theta) = 0

2. 2cos^20 (theta) + cos0 (theta) -1 = 0

- Trig -
**Reiny**, Wednesday, October 24, 2007 at 3:43pm
sinӨ + sin2Ө = 0

recall that sin2Ө = 2sinӨcosӨ

so sinӨ + sin2Ө = 0

sinӨ + 2sinӨcosӨ = 0

sinӨ(1+2cosӨ)=0

sinӨ = 0 or 2cosӨ = -1

sinӨ = 0 or or cosӨ = -1/2

Ө = 0,pi,2pi or Ө=2pi/3,4pi/3

in degrees: 0,180,360,120,240

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