posted by mel on .
What is the molarity of the Cl- ion in the solution of a sample containing 0.187g Cl- dissolved in 50.0 ml water?
use your conversion factors to determine grams to mols and then use mols of cl- per solution to convert
part a) 0.187/35.453 = 5.27 x 10^-4 moles of Cl
part b) 50 ml = .05 l
part a divided by part b = 1.05 x 10^-2 M
so part a 0.187/35=0.005 mole Cl-
part b 50mls
0.187/35.453 = 0.00527 (the above answer should be x 10^-3).
0.00527/0.05 L = 0.105 M. (above should be x 10^-1).
thanks your great