What is the molarity of the Cl- ion in the solution of a sample containing 0.187g Cl- dissolved in 50.0 ml water?
use your conversion factors to determine grams to mols and then use mols of cl- per solution to convert
part a) 0.187/35.453 = 5.27 x 10^-4 moles of Cl
part b) 50 ml = .05 l
part a divided by part b = 1.05 x 10^-2 M
0.187/35.453 = 0.00527 (the above answer should be x 10^-3).
0.00527/0.05 L = 0.105 M. (above should be x 10^-1).
so part a 0.187/35=0.005 mole Cl-
divided by
part b 50mls
thanks
thanks your great
To find the molarity (M) of the Cl- ion in the solution, you need to follow a few steps:
Step 1: Convert the mass of Cl- from grams to moles.
To do this, you will need the molar mass of Cl-.
Molar mass of Cl- = 35.453 g/mol (found on the periodic table).
To convert grams to moles, divide the mass by the molar mass:
0.187 g Cl- / 35.453 g/mol = 0.005275 mol Cl-.
Step 2: Convert the volume of the solution from milliliters to liters.
To convert milliliters to liters, divide the volume by 1000:
50.0 ml / 1000 = 0.0500 L.
Step 3: Calculate the molarity (M) using the formula:
Molarity (M) = moles of solute / liters of solution.
Molarity (M) = 0.005275 mol Cl- / 0.0500 L = 0.1055 M.
Therefore, the molarity of the Cl- ion in the solution is 0.1055 M.