Posted by robert on .
Fred begins walking toward John house at 3 mi/h. John leaves his house at the same time and walks toward Fred's house on the same path at a rate of 2 mi/h. How long will it be before they meet if the distance between the houses is 4 miles?
First, I set up an equation, 3h+2h=4. I divided 4 by 5. So, I got h=4/5. Is this right?

math 
hayley,
yes