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December 21, 2014

December 21, 2014

Posted by **Em** on Tuesday, October 23, 2007 at 4:45pm.

f(x) = 8x^3 - 3x^2 + -8x - 22

-I got 2

f(x) = x^7 + 3x^8

-I got 7

g(x) = - x + 2

I got 0

How do I graph f(x) = 4x - x^3 - x^5?

- Please check my Algebra -
**Reiny**, Tuesday, October 23, 2007 at 5:29pmdo you know calculus???

first I factored it to

f(x) = -x(x^4 + x^2 - 1)

treating the big bracket as a quadratic, I found x=0, x = ±1.11 and 2 complex roots.

finding the second derivative, setting that equal to zero and solving I got x=0 and x=5/2

so there are two points of inflection, namely at x=0 and at x=5/2

Lastly since the highest power term was negative and an odd exponent, the curve "drops" into the fourth quadrant

so your graph comes down from the second quadrant, crosses at -1.11, comes back up crossing at 0, then comes back down to cross at 1.11. It does a little S bend at x=5/2

You will have to use a different scale for your x and y axes.

- Please check my Algebra -
**Reiny**, Tuesday, October 23, 2007 at 5:30pmBTW, your first two answers are correct

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